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to tmoz
Köşe noktalarının koordinatları; A(4,3), B(1,0) ve C(2,3) olan ABC üçgeninin diklik merkezinin koordinatlaır nedir?
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to TMOZ
yükzeklikleri taşıyan iki doğrunun denklemlerini yazıp ortak çözüme gidersek sonuç gelir. (işlem kalabalığı dışında birşey göremiyorum)
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to TMOZ
A ve B noktasını kullanarak kenarın orta noktasını bulup AB doğru parçasının eğimini bulup ona dik olan doğrunun eğiminden ve orta noktadan AB nin ortak dikmesinin denklemini yazınız aynısını BC için yapınız ve iki denklemi çözünüz
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to tmoz
söz çok güzel hocam
acaba çözümünü yapabilirmisinız?
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to TMOZ
sanırım Gökhan hocam da aynı şekilde üşendi :)
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to TMOZ
işlemlerde hata riski ile beraber
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to TMOZ
çizmeniz yeterli.. rakmalr müsait:)
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iskarpinim yeter:)))))))
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to tmoz
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to TMOZ
anlamadım espiriyi ama öyle diyosan öyle:)
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hakkını helal et Murat hocam birden aklıma geldi yazayım dedim:)
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hak mevuzu bahis değil espiriyi anlayamadım kelimelere yabancı olunca..
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iskarpin ökçeli ayakkabı Murat hocam.
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to TMOZ
“Bir üçgenin kenar orta dikmelerinin bir noktada kesişeceği” iddiamızı ispatladığımıza göre asıl iddiamızın ispatına kaldığımız yerden devam edelim.
En son HIJ üçgenine (büyük üçgen) ait kenar orta dikmeler çizildiğinde bunların bir noktada kesişeceğini söylemiştik. Artık bunun doğru olduğunu biliyoruz. [HJ] ve [BC] kenarları birbirine, [IJ] ve [AB] kenarları birbirine ve de [HI] ve [AC] kenarları birbirine paralel olduğunda bunların kesenlerinin aynı tarafta olan açılarının toplamı dir. Burada da yine bir iddia var. Bunun da ispatı size kalsın. Bu bilgiye dayanarak diğer dik açıları yerleştirelim.
Şimdi şekle baktığımızda ABC üçgeninin üç kenarına ait yüksekliklerin de bir noktada kesiştiği görülüyor. O halde asıl olan “herhangi bir üçgende yükseklikler bir noktada kesişir.” iddiamızı ispatlamış olduk.
Ayrıca bu yazımıza da göz atmanızı öneririz: Euler Her Yerde! Dokuz Nokta Çemberi ve Euler Doğrusu
Matematiksel