geometri diklik merkezi / Diklik merkezi - Matematik Kafası

Geometri Diklik Merkezi

geometri diklik merkezi

Üçgende Diklik merkezi koordinatı

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BSLNMT

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Jun 1, ,  PM6/1/13

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Köşe noktalarının koordinatları; A(4,3), B(1,0) ve C(2,3) olan ABC üçgeninin diklik merkezinin koordinatlaır nedir?

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Yaşar ŞENCAN

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Jun 1, ,  PM6/1/13

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yükzeklikleri taşıyan iki doğrunun denklemlerini yazıp ortak çözüme gidersek sonuç gelir. (işlem kalabalığı dışında birşey göremiyorum)

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Gokhan Kececi

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Jun 1, ,  PM6/1/13

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A ve B noktasını kullanarak kenarın orta noktasını bulup AB doğru parçasının eğimini bulup ona dik olan doğrunun eğiminden ve orta noktadan AB nin ortak dikmesinin denklemini yazınız aynısını BC için yapınız ve iki denklemi çözünüz

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BSLNMT

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Jun 1, ,  PM6/1/13

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yaşar hocam: "İnsanın aklı kadar edebi, edebi kadar ederi vardır"

 söz çok güzel hocam

acaba çözümünü yapabilirmisinız?

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Yaşar ŞENCAN

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sanırım Gökhan hocam da aynı şekilde üşendi :)

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Yaşar ŞENCAN

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Jun 1, ,  PM6/1/13

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işlemlerde hata riski ile beraber


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murat yalcin

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Jun 1, ,  PM6/1/13

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çizmeniz yeterli.. rakmalr müsait:)

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Murat Alagoz

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Murat Alagoz

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Çizmem yetmez ama

iskarpinim yeter:)))))))

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saban derya

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murat yalcin

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anlamadım espiriyi ama öyle diyosan öyle:)

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Murat Alagoz

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hakkını helal et Murat hocam birden aklıma geldi yazayım dedim:)

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murat yalcin

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hak mevuzu bahis değil espiriyi anlayamadım kelimelere yabancı olunca..

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Murat Alagoz

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iskarpin ökçeli ayakkabı Murat hocam.

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murat yalcin

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= GC olur. O zaman AGB üçgeni de ikizkenar üçgen olur. Ve G noktasından [AB] kenarına indirdiğimiz dikme tabanı iki eşit parçaya ayırır. Dolayısıyla [AB] kenarına ait orta dikmenin de G noktasından geçmesi gerektiğini göstermiş olduk. Yani iddiamızı ispatladık.

“Bir üçgenin kenar orta dikmelerinin bir noktada kesişeceği” iddiamızı ispatladığımıza göre asıl iddiamızın ispatına kaldığımız yerden devam edelim.

yükseklik

En son HIJ üçgenine (büyük üçgen) ait kenar orta dikmeler çizildiğinde bunların bir noktada kesişeceğini söylemiştik. Artık bunun doğru olduğunu biliyoruz. [HJ] ve [BC] kenarları birbirine, [IJ] ve [AB] kenarları birbirine ve de [HI] ve [AC] kenarları birbirine paralel olduğunda bunların kesenlerinin aynı tarafta olan açılarının toplamı dir. Burada da yine bir iddia var. Bunun da ispatı size kalsın. Bu bilgiye dayanarak diğer dik açıları yerleştirelim.

Şimdi şekle baktığımızda ABC üçgeninin üç kenarına ait yüksekliklerin de bir noktada kesiştiği görülüyor. O halde asıl olan “herhangi bir üçgende yükseklikler bir noktada kesişir.” iddiamızı ispatlamış olduk.

Ayrıca bu yazımıza da göz atmanızı öneririz: Euler Her Yerde! Dokuz Nokta Çemberi ve Euler Doğrusu

Matematiksel

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batman iftar saati 2021 viranşehir kaç kilometre seferberlik ne demek namaz nasıl kılınır ve hangi dualar okunur özel jimer anlamlı bayram mesajı maxoak 50.000 mah powerbank cin tırnağı nedir